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8028453: AsynchronousSocketChannel.connect() requires SocketPermission due to bind to local address (win)

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Reviewed-by: alanb, chegar
This commit is contained in:
Michael McMahon 2013-11-20 23:33:07 +00:00
parent bf39f5917a
commit c7e80c8f2f
1 changed files with 22 additions and 1 deletions
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23
jdk/src/windows/classes/sun/nio/ch/WindowsAsynchronousSocketChannelImpl.java
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@ -31,6 +31,9 @@ import java.nio.BufferOverflowException;
import java.net.*;
import java.util.concurrent.*;
import java.io.IOException;
import java.security.AccessController;
import java.security.PrivilegedActionException;
import java.security.PrivilegedExceptionAction;
import sun.misc.Unsafe;
/**
@ -300,6 +303,19 @@ class WindowsAsynchronousSocketChannelImpl
}
}
private void doPrivilegedBind(final SocketAddress sa) throws IOException {
try {
AccessController.doPrivileged(new PrivilegedExceptionAction<Void>() {
public Void run() throws IOException {
bind(sa);
return null;
}
});
} catch (PrivilegedActionException e) {
throw (IOException) e.getException();
}
}
@Override
<A> Future<Void> implConnect(SocketAddress remote,
A attachment,
@ -330,7 +346,12 @@ class WindowsAsynchronousSocketChannelImpl
throw new ConnectionPendingException();
if (localAddress == null) {
try {
bind(new InetSocketAddress(0));
SocketAddress any = new InetSocketAddress(0);
if (sm == null) {
bind(any);
} else {
doPrivilegedBind(any);
}
} catch (IOException x) {
bindException = x;
}